Integrand size = 28, antiderivative size = 70 \[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=-\frac {2 i e^2 \sqrt {e \sec (c+d x)}}{a d}+\frac {2 e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{a d} \]
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Time = 0.10 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.107, Rules used = {3582, 3856, 2720} \[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=\frac {2 e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{a d}-\frac {2 i e^2 \sqrt {e \sec (c+d x)}}{a d} \]
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Rule 2720
Rule 3582
Rule 3856
Rubi steps \begin{align*} \text {integral}& = -\frac {2 i e^2 \sqrt {e \sec (c+d x)}}{a d}+\frac {e^2 \int \sqrt {e \sec (c+d x)} \, dx}{a} \\ & = -\frac {2 i e^2 \sqrt {e \sec (c+d x)}}{a d}+\frac {\left (e^2 \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{a} \\ & = -\frac {2 i e^2 \sqrt {e \sec (c+d x)}}{a d}+\frac {2 e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{a d} \\ \end{align*}
Time = 1.36 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.70 \[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=\frac {2 e^2 \left (-i+\sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )\right ) \sqrt {e \sec (c+d x)}}{a d} \]
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Time = 6.63 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.96
method | result | size |
default | \(-\frac {2 i e^{2} \left (F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \cos \left (d x +c \right )+F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}+1\right ) \sqrt {e \sec \left (d x +c \right )}}{a d}\) | \(137\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.07 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.90 \[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=-\frac {2 \, {\left (i \, \sqrt {2} e^{2} \sqrt {\frac {e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )} + i \, \sqrt {2} e^{\frac {5}{2}} {\rm weierstrassPInverse}\left (-4, 0, e^{\left (i \, d x + i \, c\right )}\right )\right )}}{a d} \]
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\[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=- \frac {i \int \frac {\left (e \sec {\left (c + d x \right )}\right )^{\frac {5}{2}}}{\tan {\left (c + d x \right )} - i}\, dx}{a} \]
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Exception generated. \[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=\text {Exception raised: RuntimeError} \]
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\[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=\int { \frac {\left (e \sec \left (d x + c\right )\right )^{\frac {5}{2}}}{i \, a \tan \left (d x + c\right ) + a} \,d x } \]
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Timed out. \[ \int \frac {(e \sec (c+d x))^{5/2}}{a+i a \tan (c+d x)} \, dx=\int \frac {{\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^{5/2}}{a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}} \,d x \]
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